So we can fit 40 of the gift boxes per base area, but we need to find out how many gifts will fit in the whole box. Five more layers of cubes can be placed on top of the base layer to fill the box. Now that the box contains 6 layers of gifts, with 40 gifts on each layer, the box will be filled by a total of 240 gifts. For this example, we used the method for finding the volume of a prism to find how many 1 cm3 gift boxes can fit.

Laser spectroscopyprinciple

If we take the proportion of the areas of the base of our box and the gifts we can find how many cubes we can fit in the base area of the box:

The volume of a cylinder follows the same logic as the prism.  The only difference is a change in the base, which is now a circle. Then the volume of the cylinder is

The (0,0) and (0, 1) bands of the C(4)Sigma(-)-X(4)Sigma(-) electronic transition of VS (near 809 and 846 nm, respectively) have been recorded at high resolution by laser-induced fluorescence, following the reaction of laser-ablated vanadium atoms with CS2 under supersonic free-jet conditions. A least squares fit to the resolved hyperfine components of the rotational lines gives the rotational constants and bond lengths as C(4)Sigma(-): B-o = 0.188898 +/- 0.000027 cm(-1), r(o) = 2.1315 Angstrom; X(4)Sigma(-): B-0 = 0.203684 +/- 0.000025 cm(-1), r(o) = 2.0526 Angstrom. The electron spin parameters for the two states show that there are some similarities between the states of VS and those of VO, but the hyperfine parameters show that the compositions of the partly filled molecular orbitals are by no means the same. The ground state Fermi contact parameter of VS, b (X(4)Sigma(-)), is only 58% of that of the ground state of VO, which implies that the sigma orbital of the ground sigmadelta(2) electron configuration has less than 50% vanadium 4s character. Similarly, the excited state Fermi contact parameter, b(C(4)Sigma(-)), is very much smaller than that of VO. No local rotational perturbations have been found in the C(4)Sigma(-) state of VS, though an internal hyperfine perturbation between the F-2 and F-3 electron components at low N confuses the hyperfine structure and induces some forbidden (DeltaJ = +/-2) rotational branches. (C) 2003 Elsevier Science (USA). All rights reserved.

Laser Spectroscopyppt

The box shown is 10 cm wide, 4 cm long, and 6 cm high. If you have gifts that are cubes, with a length of 1 cm, how many cubes will fit inside the box? What is the volume of the box?

To find the volume of a cone, we follow the same principle as for the cylinder.  So we use the same method, but the base is now circular. Then we have

Laser spectroscopyPDF

As we already saw, the volume of a prism is the area of the base times the height of the prism. The volume of the pyramid has the same base area and height as the prism, but with less volume than the prism. The volume of the pyramid is one third the volume of the prism.

Volume is the quantity of space, calculated in cubic units, which a body occupies. The following lesson will explain the general formulas used to find the volume of the most frequently used solid figures: prisms, cylinders, pyramids, and cones.