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There is a calculator that will do this at https://www.scantips.com/lights/fieldofview.html (Option 6). The geometry is shown at bottom of that page, however, you must use Trig for angles.

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There are basically three types of optical fiber: single mode, multimode graded index, and multimode step-index. They are characterized by the way light travels ...

The article specifies that the horizontal FOV is 47°, so we have to use A = 640/2 = 320, a = 47°/2 = 23.5°, which give F = 736 pixels.

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Standard infrared (IR) 5mm LEDs. These work well for making remote controls or beam break detectors.

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The triangles (large and small) are similar, that is angles are the same. So Angle of view will be the same as top angle (at the lens) of the smaller triangle. From that, since you know what sensor size and angle of view is, you can calculate focal length in pixels, as @remco calculated for you.

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It is what Hermann said, focal length is NOT measured in pixels. I strongly doubt the engineering journal said focal length was pixels.

Acrylic, also called plexiglass, is becoming a popular alternative to glass windows. While manufacturers have used waterproof acrylic windows for years, ...

As your sensor size is given in pixels (assumed square pixels!), your focal length will also be in pixels. To get it in a more usual unit (m), you need to know the pixel size.

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It's basic geometry: you have a right angle triangle, with half the FOV as one of the angles (a), and half your image size as the opposite side (A). To calculate the focal length F, use tan(a) = A/F, which gives F = A/tan(a).

What you need to know for field of view is the camera sensor size (or film size) measured in mm. You must compute with sensor dimensions in mm.

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In fact, units of the sensor size should be exactly the same as units of the focal length to make sense of F=A/tan(a). What you can get from that is, if you have bigger pixels (in cm), you will need larger focal length (in cm) for same field of view and number of pixels.

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