Let us see the definition of the reflection coefficient, it is the ratio of the peak value of E in the reflected wave to the peak value of E in the incident wave.

5 things thatabsorb light

sin^{2}\theta {B||}= \frac{1-\frac{\mu {2}\varepsilon {1}}{\mu {1}\varepsilon {2}}}{1-\left ( \epsilon {1}/\epsilon _{1} \right )^{2}} —(2)

The absorption of photons creates both a majority and a minority carrier. In many photovoltaic applications, the number of light-generated carriers are of orders of magnitude less than the number of majority carriers already present in the solar cell due to doping. Consequently, the number of majority carriers in an illuminated semiconductor does not alter significantly. However, the opposite is true for the number of minority carriers. The number of photo-generated minority carriers outweighs the number of minority carriers existing in the doped solar cell in the dark (because in doping the minority carrier concentration is so small), and therefore the number of minority carriers in an illuminated solar cell can be approximated by the number of light generated carriers.

What does it mean toabsorb light

sin^{2}\theta {B\perp }= \frac{1-\frac{\mu {1}\varepsilon {2}}{\mu {2}\varepsilon {1}}}{1-\left ( \mu {1}/\mu _{2} \right )^{2}} —(1)

Absorption oflightExamples

Hope so , this article has given you a valid reason why the Brewster angle is not defined for perpendicular polarization.

The Brewster angle is also called the polarization angle because the light that reflects from a surface at this angle is entirely polarized perpendicular to the plane of incidence.

What happens whenlightis absorbed

Photons incident on the surface of a semiconductor will be either reflected from the top surface, will be absorbed in the material or, failing either of the above two processes, will be transmitted through the material. For photovoltaic devices, reflection and transmission are typically considered loss mechanisms as photons which are not absorbed do not generate power. If the photon is absorbed it has the possibility of exciting an electron from the valence band to the conduction band. A key factor in determining if a photon is absorbed or transmitted is the energy of the photon. Therefore, only if the photon has enough energy will the electron be excited into the conduction band from the valence band. Photons falling onto a semiconductor material can be divided into three groups based on their energy compared to that of the semiconductor band gap:

We know that an EM wave carries electromagnetic power with it. It depends on the intrinsic impedance of the medium it travels.

Mathematical reason :- Let us see mathematical proof, that Why the Brewster angle is not defined for perpendicular polarization.

Absorb lightwavelength

Brewster angle is the angle of incidence for which the reflection coefficient is zero. But, as we know, we have two cases of polarizations viz. perpendicular and parallel.

Medium 1 will have intrinsic impedance \eta_{1} and medium 2 will have intrinsic impedance as \eta_{2}. So, due to impedance mismatching, some power gets reflected back we called it a reflected wave and the remaining power which gets transmitted back into another medium is called a transmitted wave.

And, you must be aware that Brewster angle is not practically defined for the perpendicular polarization. Let’s see, why?

When the electromagnetic wave travels from one medium to another then due to impedance mismatching some power gets transmitted into one medium while some power gets reflected back into another medium.