Broadband achromatic aberration general conformal ... - achromatic aberration
Opticallens
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Lens equation
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A \(2.00-\mathrm{cm}\) -high object is placed \(3.00 \mathrm{~cm}\) in front of a concave mirror. If the image is \(5.00 \mathrm{~cm}\) high and virtual, what is the focal length of the mirror?
Lensmakers formula
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Lensformula
A spherical mirror is to be used to form an image, five times as tall as an object, on a screen positioned \(5.0 \mathrm{~m}\) from the mirror, (a) Describe the type of mirror required. (b) Where should the mirror be positioned relative to the object?
Converginglens
Lensmaker formula
Magnification oflensformula
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An object is placed \(15.0 \mathrm{~cm}\) from a first converging lens of focal length \(10.0 \mathrm{~cm} .\) A second converging lens with focal length \(5.00 \mathrm{~cm}\) is placed \(10.0 \mathrm{~cm}\) to the right of the first converging lens. (a) Find the position \(q_{1}\) of the image formed by the first converging lens. (b) How far from the second lens is the image of the first lens? (c) What is the value of \(p_{2}\), the object position for the second lens? (d) Find the position \(q_{2}\) of the image formed by the second lens. (e) Calculate the magnification of the first lens. (f) Calculate the magnification of the second lens. (g) What is the total magnification for the system? (h) Is the final image real or virtual? Is it upright or inverted?
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(a) Use the thin-lens equation to derive an expression for \(q\) in terms of \(f\) and \(p\). (b) Prove that for a real object and a diverging lens, the image must always be virtual. Hint: Set \(f=-|f|\) and show that \(q\) must be less than zero under the given conditions. (c) For a real object and converging lens, what inequality involving \(p\) and \(f\) must hold if the image is to be real?
A converging lens is placed \(30.0 \mathrm{~cm}\) to the right of a diverging lens of focal length \(10.0 \mathrm{~cm}\). A beam of parallel light enters the diverging lens from the left, and the beam is again parallel when it emerges from the converging lens. Calculate the focal length of the converging lens.
A diverging lens has a focal length of \(20.0 \mathrm{~cm}\). Locate the images for object distances of (a) \(40.0 \mathrm{~cm}\), (b) \(20.0 \mathrm{~cm}\), and (c) \(10.0 \mathrm{~cm} .\) For each case, state whether the image is real or virtual and upright or inverted, and find the magnification.