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For example, if there is a point charge of 2 microcoulombs located 3 meters away from a test charge of 5 microcoulombs, the electric field at that point can be calculated as E = (k * 2 * 5) / (3^2) = 3.33 N/C. This means that the test charge will experience an electric force of 3.33 Newtons in the direction of the point charge.

Theelectric potential at points in an x-y plane is given by

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The electric field is a vector quantity that describes the strength and direction of the force experienced by a charged particle in the presence of other charged particles.

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The electric field is represented by the equation E = F/q, where E is the electric field, F is the force, and q is the charge. This equation can also be written as E = kQ/r^2, where k is the Coulomb's constant, Q is the source charge, and r is the distance between the source charge and the point where the electric field is measured.

The electric field is directly proportional to the magnitude of the charge and inversely proportional to the square of the distance between the charges, as described by Coulomb's Law.

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The direction of the electric field is always in the direction that a positive test charge would move if placed at that point. This can be determined by using the principle of superposition and considering the direction of the electric forces from all nearby charges.

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