Suggests that - no jest - Edmund Tome Jesty participated in the following tournaments:16th British Championship 1923, Southsea 13th British Championship 1920, Edinburgh

Optical distortionmeaning

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Distortion opticalcalculator

click for larger viewAnalysis by Houdini 4 d 25 dpa done 1. = (0.10): 15...Qc5 16.Nxg6 hxg6 17.Rb1 g5 18.Bg3 Qxc3 19.Re3 Qc5 20.Qe1 Rad8 21.Rc3 Qe7 22.Qe3 c6 23.Bd3 Rd4 24.f3 Rfd8 25.Rc4 R4d7 26.Kg2 Qa3 27.Qc1 Qe7 28.Rc3 a6 29.Qd2 Rd4 30.Be5 Nf4+ 31.Bxf4 gxf4 32.Rb6 Ne8 33.Qxf4 Nd6 34.Rcb3 Ra4 35.a3 Nb5 2. + / = (0.41): 15...Rad8 16.Qf3 Qc5 17.Nxg6 hxg6 18.Ba4 g5 19.Bg3 a5 20.Bb3 Qc6 21.Bxe6 fxe6 22.Qe3 Rd7 23.Kg2 Qa4 24.Re2 Nh7 25.f3 Rfd8 26.h4 gxh4 27.Bxh4 Rf8 28.Bg3 Rdf7 29.Rb1 b6 30.Qd4 Qxa2

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http://www.saund.co.uk/britbase/pgn...Suggests that - no jest - Edmund Tome Jesty participated in the following tournaments:16th British Championship 1923, Southsea 13th British Championship 1920, Edinburgh

Distortion opticalexamples

1. = (0.10): 15...Qc5 16.Nxg6 hxg6 17.Rb1 g5 18.Bg3 Qxc3 19.Re3 Qc5 20.Qe1 Rad8 21.Rc3 Qe7 22.Qe3 c6 23.Bd3 Rd4 24.f3 Rfd8 25.Rc4 R4d7 26.Kg2 Qa3 27.Qc1 Qe7 28.Rc3 a6 29.Qd2 Rd4 30.Be5 Nf4+ 31.Bxf4 gxf4 32.Rb6 Ne8 33.Qxf4 Nd6 34.Rcb3 Ra4 35.a3 Nb5 2. + / = (0.41): 15...Rad8 16.Qf3 Qc5 17.Nxg6 hxg6 18.Ba4 g5 19.Bg3 a5 20.Bb3 Qc6 21.Bxe6 fxe6 22.Qe3 Rd7 23.Kg2 Qa4 24.Re2 Nh7 25.f3 Rfd8 26.h4 gxh4 27.Bxh4 Rf8 28.Bg3 Rdf7 29.Rb1 b6 30.Qd4 Qxa2

Distortion opticalformula

Analysis by Houdini 4 d 25 dpa done 1. = (0.10): 15...Qc5 16.Nxg6 hxg6 17.Rb1 g5 18.Bg3 Qxc3 19.Re3 Qc5 20.Qe1 Rad8 21.Rc3 Qe7 22.Qe3 c6 23.Bd3 Rd4 24.f3 Rfd8 25.Rc4 R4d7 26.Kg2 Qa3 27.Qc1 Qe7 28.Rc3 a6 29.Qd2 Rd4 30.Be5 Nf4+ 31.Bxf4 gxf4 32.Rb6 Ne8 33.Qxf4 Nd6 34.Rcb3 Ra4 35.a3 Nb5 2. + / = (0.41): 15...Rad8 16.Qf3 Qc5 17.Nxg6 hxg6 18.Ba4 g5 19.Bg3 a5 20.Bb3 Qc6 21.Bxe6 fxe6 22.Qe3 Rd7 23.Kg2 Qa4 24.Re2 Nh7 25.f3 Rfd8 26.h4 gxh4 27.Bxh4 Rf8 28.Bg3 Rdf7 29.Rb1 b6 30.Qd4 Qxa2

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Pincushiondistortion

2. + / = (0.41): 15...Rad8 16.Qf3 Qc5 17.Nxg6 hxg6 18.Ba4 g5 19.Bg3 a5 20.Bb3 Qc6 21.Bxe6 fxe6 22.Qe3 Rd7 23.Kg2 Qa4 24.Re2 Nh7 25.f3 Rfd8 26.h4 gxh4 27.Bxh4 Rf8 28.Bg3 Rdf7 29.Rb1 b6 30.Qd4 Qxa2

LensdistortionExamples

There are six plate constants in each coordinate, and therefore a minimum of six comparison stars are necessary to solve for them. If more that six are used (which is highly desirable) a least squares solution can be obtained for the plate constants. One then follows the same procedure as in the linear case.

Analysis by Houdini 4 d 25 dpa done 1. = (0.10): 15...Qc5 16.Nxg6 hxg6 17.Rb1 g5 18.Bg3 Qxc3 19.Re3 Qc5 20.Qe1 Rad8 21.Rc3 Qe7 22.Qe3 c6 23.Bd3 Rd4 24.f3 Rfd8 25.Rc4 R4d7 26.Kg2 Qa3 27.Qc1 Qe7 28.Rc3 a6 29.Qd2 Rd4 30.Be5 Nf4+ 31.Bxf4 gxf4 32.Rb6 Ne8 33.Qxf4 Nd6 34.Rcb3 Ra4 35.a3 Nb5 2. + / = (0.41): 15...Rad8 16.Qf3 Qc5 17.Nxg6 hxg6 18.Ba4 g5 19.Bg3 a5 20.Bb3 Qc6 21.Bxe6 fxe6 22.Qe3 Rd7 23.Kg2 Qa4 24.Re2 Nh7 25.f3 Rfd8 26.h4 gxh4 27.Bxh4 Rf8 28.Bg3 Rdf7 29.Rb1 b6 30.Qd4 Qxa2

I refer here to pincushion or barrel distortion introduced by the optical system. This results in a displacement of the stellar images towards or away from the plate centre. Unlike differential refraction or aberration of light, the stellar displacements are symmetric with respect to inversion through the plate centre. This is also true of the optical aberration known as coma. A comatic stellar image results in a displacement of the centre of the stellar image away from the plate centre. Thus we can deal with distortion and coma in a similar manner.

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\[η − y = a^\prime x^2 + 2h^\prime xy + b^\prime y^2 + 2g^\prime x + f^\prime y + c^\prime . \label{11.3.21} \tag{11.3.21}\]

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This page titled 11.3.5: Optical Distortion is shared under a CC BY-NC 4.0 license and was authored, remixed, and/or curated by Jeremy Tatum via source content that was edited to the style and standards of the LibreTexts platform.