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Diffraction by gratingexamples
When light passes through the slits of the diffraction grating, the path difference at the zeroth order maximum is zero At the first order maxima, there is constructive interference, hence the path difference is λ Therefore, at the nth order maxima, the path difference is equal to nλ
Note that while you will be expected to know some applications of diffraction gratings, you will not be tested on specific apparatus or techniques such as spectrometry.When describing the use of spectrometers, avoiding using vague terms such as observe spectra’, ‘spectroscopy’, ‘view absorption / emission spectrum’, ‘compare spectra’, ‘look at light from stars’.
Diffraction by gratingequation
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When light passes through the slits of the diffraction grating, the path difference at the zeroth order maximum is zero At the first order maxima, there is constructive interference, hence the path difference is λ Therefore, at the nth order maxima, the path difference is equal to nλ
Diffraction gratingformula
Diffraction gratingPDF
Using trigonometry, an expression for the first order maxima can be written: Where: θ = the angle between the normal and the maxima λ = the wavelength of the light (m) d = the slit separation (m)
What isgratingelement
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Diffraction gratings are most commonly used in spectrometers. These devices play a crucial role in areas of physics such as atomic physics and astrophysics
An experiment was set up to investigate light passing through a diffraction grating with a slit spacing of 1.7 µm. The fringe pattern was observed on a screen. The wavelength of the light is 550 nm.
Diffraction by gratingexperiment
Take care that the angle θ is the correct angle taken from the centre and not the angle taken between two orders of maxima.
Therefore, in general, where the path difference is nλ: A small rearrangement leads to the equation for the diffraction grating:d sin θn = nλ
Once you have completed the course, you will be asked a series of questions to check your knowledge and understanding. These are based on the learning objectives for the course and have a pass mark of 100%.