Looking at it the other way round, the copper(II) ions are removing electrons from the magnesium to create the magnesium ions. The copper(II) ions are acting as an oxidising agent.

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It is essential that you remember these definitions. There is a very easy way to do this. As long as you remember that you are talking about electron transfer:

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You would need to use an oxidising agent to remove the hydrogen from the ethanol. A commonly used oxidising agent is potassium dichromate(VI) solution acidified with dilute sulphuric acid.

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An oxidising agent is substance which oxidises something else. In the above example, the iron(III) oxide is the oxidising agent.

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Ethanal can also be reduced back to ethanol again by adding hydrogen to it. A possible reducing agent is sodium tetrahydridoborate, NaBH4. Again the equation is too complicated to be worth bothering about at this point.

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This page looks at the various definitions of oxidation and reduction (redox) in terms of the transfer of oxygen, hydrogen and electrons. It also explains the terms oxidising agent and reducing agent.

From Proto-Celtic *regeti (“to extend, stretch, straighten”),[1] from Proto-Indo-European *h₃reǵ- (“to straighten, stretch, rule”).[2][3]

Oxidisingsubstance symbol

These are old definitions which aren't used very much nowadays. The most likely place you will come across them is in organic chemistry.

Note:  The equation for this is rather complicated for this introductory page. If you are interested, you will find a similar example (ethanol to ethanoic acid) on the page dealing with writing equations for redox reactions.

Copper(II) oxide and magnesium oxide are both ionic. The metals obviously aren't. If you rewrite this as an ionic equation, it turns out that the oxide ions are spectator ions and you are left with:

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This is potentially very confusing if you try to learn both what oxidation and reduction mean in terms of electron transfer, and also learn definitions of oxidising and reducing agents in the same terms.

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From Middle English rigide, from Latin rigidus (“stiff”), from rigeō (“I am stiff”). Compare rigor. Merged with Middle English rigged, rygged, rugged (“upright like a spine, rigid”, literally “ridged”), from ridge +‎ -ed.

If you look at the equation above, the magnesium is reducing the copper(II) ions by giving them electrons to neutralise the charge. Magnesium is a reducing agent.

Personally, I would recommend that you work it out if you need it. The argument (going on inside your head) would go like this if you wanted to know, for example, what an oxidising agent did in terms of electrons: